Find the no. of integer pairs of (m,n) satisfying the relation m^2+mn+n^2=1.(a)2(b)4(c)6(d)8
4
solution.> make it a quadratic in m 2m= -n+(4-3n^2)^(1/2) or 2m= -n-(4-3n^2)^(1/2)now 4-3n^2 > 0and n is integer.'. n= -1,0,1putting back n in equation gives (m,n)= (0,-1);(-1,0);(1,0);(0,1);(1,-1);(-1,1)now distinct pairs = 6(C)
sir, will you please help me in knowing about the kind of questions that are asked in the interview?
where can i get test of mathematics at 10+2 level in delhi. Can anyone please help.
Find the no. of integer pairs of (m,n) satisfying the relation m^2+mn+n^2=1.
ReplyDelete(a)2
(b)4
(c)6
(d)8
4
Delete4
Deletesolution.>
Deletemake it a quadratic in m
2m= -n+(4-3n^2)^(1/2)
or
2m= -n-(4-3n^2)^(1/2)
now 4-3n^2 > 0
and n is integer
.'. n= -1,0,1
putting back n in equation gives
(m,n)=
(0,-1);(-1,0);(1,0);(0,1);(1,-1);(-1,1)
now distinct pairs = 6(C)
sir, will you please help me in knowing about the kind of questions that are asked in the interview?
ReplyDeletewhere can i get test of mathematics at 10+2 level in delhi. Can anyone please help.
ReplyDelete